Re: private constructor and new operator overloading.
you need to write a new static member function to instead of the operator
new.
for instance:
class MyClass {
public:
static MyClass* New();
// using keyword "protected" means it can be derived.
// using keyword "private" means it cannot be derived any more.
protected:
MyClass();
};
int main() {
....
MyClass* pMyClass = MyClass::New();
....
delete pMyClass;
....
}
"siddhu" <siddharth.sng@gmail.com>
??????:1178898305.430200.284730@h2g2000hsg.googlegroups.com...
On May 11, 11:27 am, siddhu <siddharth....@gmail.com> wrote:
A correction in the code snippet..
Dear Experts,
I want to make a class whose objects can be created only on heap.
I used the following approach.
class ss
{
ss(){}
public:
void* operator new(size_t sz)
{
cout<<"in new"<<endl;
return malloc(sz); //return new char[sz];
//sorry..... my
mistake
}
void operator delete(void* m)
{
free(m);
}
};
int main()
{
ss* s = new ss;
return 0;
}
But when I do
ss* s = new ss;
compiler complains that constructor ss::ss() is private.
As operator new function is member of class so compiler should not
complain because operator new function can call the default
constructor even if it is private.
I am surprised and confused.
Suggestions would be of great help.
Regards,
Siddharth
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