Re: Newbie inheritance question

From:
 "sumedh....." <sumedhsakdeo@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 20 Jul 2007 11:31:39 -0000
Message-ID:
<1184931099.503931.280310@57g2000hsv.googlegroups.com>
On Jul 19, 2:07 pm, ke...@bytebrothers.co.uk wrote:

Hi all, I'm getting confused again, so someone please take pity and
explain. I've got something like this:

class Base
{
   void do_work(string&, string&, int&);

};

class Derived : public Base
{
   void do_work(char*, char*, int&);

};

int main()
{
   Derived MyObj;
   string sString, bString;

   MyObj.do_work(aString, bString, 123);

}

This gives a compile-time error that basically says

no matching function for call to `Derived::do_work(string&, string&,
int)'
candidates are: void Derived::do_work(char*, char*, int&)

Why does the compiler not use the matching function from the Base
class? I can work around it by doing something like this:

int main()
{
   Base* ptr = new Derived();
   string aString, bString;

   ptr->do_work(aString, bString, 123);
   delete ptr;

}

but that seems to sort of defeat the purpose of inheritance, to my
newbie eyes at least.


well if you want to do anything like this which is function
overriding... u need to have exactly same fucntions in base and
dervied class. Well i think this serves ur purpose....
Cheers,
Sumedh

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