Re: If a class has a virtual destructor

From:
HumbleWorker <amardeep.developer@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Tue, 7 Aug 2007 10:20:40 CST
Message-ID:
<1186493868.081908.306740@q3g2000prf.googlegroups.com>

a) A virtual destructor
b) A virtual function <ret>Name(int param1, int param2) const;

For point b, specifically I am interested in finding out how to detect
the virtuality of the call.


Try this one
#include "stdafx.h"
#include <iostream>

// class that has to be tested for
// virtual destructor
class CVirtualDtor
{
public:

    virtual ~CVirtualDtor ()
    {
        std::cout << "virtual ~CVirtualDtor ()\n";
    };
};

// class that has to be tested for
// virtual destructor
class CNoVirtualDtor
{
public:

    ~CNoVirtualDtor ()
    {
        std::cout << "~CNoVirtualDtor ()\n";
    };
};

// this is the template function
//****************FUNCTION STARTS*******************//

template<typename T>
bool HasVirtualDtor ()
{
    // a boolean return
    static bool bRet = false;

    // since CDerived has no member objects
    // there is no harm if its destructor is skipped
    // during this test
    class CDerived : public T
    {
    public:
        CDerived () {bRet = false;}
        ~CDerived () {bRet = true;}
    };

    // we shall call virtual mechanism to play here
    // and the virtual d-tor will be revealed !
    // assume success of new
    T* oDerived = new CDerived ();
    delete oDerived;

    return bRet;
};

//****************FUNCTION ENDS*******************//

int _tmain(int argc, _TCHAR* argv[])
{
    std::cout << "CNoVirtualDtor has a virtual d-tor ? : " <<
HasVirtualDtor<CNoVirtualDtor>() << std::endl;
    std::cout << "CVirtualDtor has a virtual d-tor ? : " <<
HasVirtualDtor<CVirtualDtor>() << std::endl;
    return 0;
}

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