Re: Program to find occurences of a word in a file

From:
terminator <farid.mehrabi@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 23 Nov 2007 12:37:01 -0800 (PST)
Message-ID:
<07144be8-141b-42a3-8d4f-eab81d0b52a3@a39g2000pre.googlegroups.com>
On Nov 23, 9:31 pm, "Tadeusz B. Kopec" <tko...@NOSPAMPLEASElife.pl>
wrote:

On Fri, 23 Nov 2007 04:06:38 -0800, terminator wrote:

all what I get is that in case of default constructing ,intrinsic
rvalues go zero.

#include <iostream>
#include <conio.h>
using namespace std;

template <typename T> struct testd{
   T t;
   testd():t(){};
};

int main(){
   testd<long> tl, *ptr=new testd<long> ; cout <<"One\n"<< tl.t << endl;
   cout <<"Two\n"<< ptr->t << endl;
   delete ptr;

   cout <<"Three\n"<< long() << endl;

   long* l=new long;
   cout <<"Four\n"<< l << endl;
   new(l)long();
   cout <<"Five\n"<< l << endl;

   delete l;

   cout<<"Six\n" << testd<long>().t <<endl;

   getch();
   return 0;
};

only the third output comes zero.
so in case the container uses placement new nop is done and it cannot
zero-default the value.
now I believe that it is the default allocator - not the ctor - who
resets the allocated bytes to zero .


Well, I tried it by myself and in all except fourth and fifth I got zero.
When I changed fourth and fifth to print pointee instead of pointer I
also got zeroes.

silly me. but derefrencing did not zero mine.

best,
FM.

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