Re: derived class pointer to base class object

From:

Rahul <sam_cit@yahoo.co.in>

Newsgroups:

comp.lang.c++

Date:

Mon, 3 Dec 2007 08:40:03 -0800 (PST)

Message-ID:

<afdcef64-eee4-4a0f-8ba8-1e0ebf341137@e10g2000prf.googlegroups.com>

On Dec 3, 9:27 pm, "Victor Bazarov" <v.Abaza...@comAcast.net> wrote:

Rahul wrote:

  I was just playing around virtual functions and landed up with the
following,

class Base1
     {
       public: virtual void sample()
                  {
                    printf("base::sample\n");
                  };
     };

     class Derived1: public Base1
     {
       public: void sample()
                  {
                    printf("derived::sample\n");
                  };
     };

int main()
{
Derived1 *ptr = reinterpret_cast<Derived1 *> (new Base1());
ptr->sample();
return(0);
}

this invokes the sample() of base version, but if i declare sample as
a ordinay (non-virtual) function, the sample() of derived class is
invoked. I'm wondering how? Can anyone help in this regard?

The code 'ptr->sample()' has undefined behaviour because casting from
a base class to a derived class is NOT what 'reinterpret_cast' is for.
Either 'static_cast' or 'dynamic_cast' are used for that.

In your case 'dynamic_cast' should return NULL since the object is
NOT of type 'derived', which should suggest that 'static_cast' is not
what you need either. You only use 'static_cast' in this situation
if you *know exactly* that the pointer was obtained by converting
some derived class object into the base.

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask

Then, how do you suggest to type cast from Base class object to
derived class pointer?

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