Re: Typecasting a class pointer

From:

"czp.opensource@gmail.com" <czp.opensource@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Tue, 12 Feb 2008 17:35:42 -0800 (PST)

Message-ID:

<aec6ac83-933e-4ebd-941b-f6c301f3f66a@v17g2000hsa.googlegroups.com>

On Feb 13, 9:24 am, Antonio Rivas <cha...@telefonica.net> wrote:

AnonMail2...@gmail.com escribi=F3:

On Feb 12, 7:42 pm, Antonio Rivas <cha...@telefonica.net> wrote:

I've got a code that is the following way:

classes.h
class claseA {
     public:
         claseA();
         ~claseA();

};

class claseB {
     public:
         claseB();
         claseB( const claseA& aClase);
         ~claseB();

};

main.cpp
#include "classes.h"

int main () {
    claseA* pClaseA = new claseA();
    claseB* pClaseB = new claseB( pClaseA* ); // compiler error

....

    return 0;

};

I get a "expected primary-expression before ')'" error at the marked
line. Seems that try pass a class using a pointer is not valid but when=

I try to typecast the dereferenced pointer this way:

classB* pClaseB = new claseB( (claseA)pClaseA* );

I get a different compiler error: "no matching function call to
'claseA::claseA(claseA*&)'

In case this compiler error is a precedence error I tried too the
following code line:

classB* pClaseB = new claseB( (claseA)(pClaseA*) );

but I get again the first compiler error: expected primary-expression
before ')'

Is clear that I'm missing something, or is just that cannot be done thi=

way?

Use *pClaseA instead of pClaseA* as the argument supplied to the
function call.

HTH

I admit that pointers in C/C++ are quite confusing sometimes. It worked
like a charm. It's clear that I must study much more the topic about
pointers :)

Thank you :)

hi:
claseB( const claseA& aClase);
here means reference, so don't pass a point to it