Re: about temporary object

From:
raicuandi <raicuandi@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sat, 2 Aug 2008 23:42:40 -0700 (PDT)
Message-ID:
<494c8cb9-365a-4238-b15e-2227a63a0152@e53g2000hsa.googlegroups.com>
On Aug 3, 1:00 pm, cxf <cxf....@gmail.com> wrote:

class A{
public:
        A()
                {
                       func(0);
                 };
        virtual void func(int data)
                {
                        printf("A1 :%d\n",data);
                }
        virtual void func(int data) const
                {
                       printf("A2 :%d\n",data);
                }

};

A().func(1) invoke which function? ,why?
I think it is " void func(int data) const", because A() return a
temporary object, which should be const. But when it is executed with
vc 6.0, it invokes "void func(int data)"!

please help me, thank you!


The line:

A().func(1);

Means 2 invocations of "func". The first one is going to be the non-
const one, because its called from inside the constructor. The
constructor is suppose to modify the instance, therefore it calls the
non-const one.

As for the second "func" call, its again the non-const one, for
obvious reasons: "A()" returns an A, not a "const A".

Observe:
A().func(1);
Output:
A1 :0
A1 :1

Now:
const A* a = new A(); // "a" is now declared const
a->func(1);
Output:
A1 :0
A2 :1

However:
A* a = new A(); // "a" NOT declared const, defaults to non-const
a->func(1);
So obviously:
A1 :0
A1 :1

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