Question on auto_ptr, Which function will call first?

Hi, everyone, I'm studying the <<Thinking in C++>> volume Two. In
Chapter One, the example code : Auto_ptr.cpp
//-------------------------------------------------------
#include <memory>
#include <iostream>
#include <cstddef>
using namespace std;

class TraceHeap {
    int i;
public:
    static void* operator new(size_t siz) { //*****NOTE A
        void* p = ::operator new(siz);
        cout << "Allocating TraceHeap object on the heap "
            << "at address " << p << endl;
        return p;
    }
    static void operator delete(void* p) {
        cout << "Deleting TraceHeap object at address "
            << p << endl;
        ::operator delete(p);
    }
    TraceHeap(int i) //*******NOTE B
        : i(i)
    {
        ;
    }
    int getVal() const { return i; }
};

int main() {
    auto_ptr<TraceHeap> pMyObject(new TraceHeap(5));
    cout << pMyObject->getVal() << endl; // Prints 5
}
//------------------------------------------------------------------

My question is :

In My code: which code will be called first? The *NOTE A* or *NOTE B* ?
And Why?

I'm debugging through this code and found that *NOTE A* will called
first. Can someone explained it?
When I trace into the *new* function, the *siz* value is 4. I don't know
why it will be 4?

Thank you for reading my message.