Re: This HAS to be UB...

From:
"Chris M. Thomasson" <no@spam.invalid>
Newsgroups:
comp.lang.c++
Date:
Fri, 3 Oct 2008 22:22:17 -0700
Message-ID:
<OZCFk.1620$V72.625@newsfe09.iad>
"Victor Bazarov" <v.Abazarov@comAcast.net> wrote in message
news:gc39rg$q2m$1@news.datemas.de...

Chris M. Thomasson wrote:

Keep in mind that I am a C programmer; well, anyway here is the C++
program...

[...]

Well, the default implementation of the operator delete[] does *not* have
the "size" argument. In fact there are two allowed declarations of the
operator delete[]:

    void operator delete[](void* ptr) throw();

and

    void operator delete[](void* ptr, const std::nothrow&) throw();

I'm not sure what else to tell you.


I think that

void operator delete [](void*, std::size_t) throw();

is a valid declaration. I mean, even Comeau compiles the following program
without any warnings:
____________________________________________________________________
#include <cstdio>
#include <cstdlib>
#include <new>

struct custom_allocator {
  static void* allocate(std::size_t size)
   throw(std::bad_alloc) {
    void* const mem = std::malloc(size);
    if (! mem) {
      throw std::bad_alloc();
    }
    std::printf("custom_allocator::allocate(%p, %lu)\n",
      (void*)mem, (unsigned long)size);
    return mem;
  }

  static void deallocate(void* const mem, std::size_t size)
   throw() {
    if (mem) {
      std::printf("custom_allocator::deallocate(%p, %lu)\n",
        (void*)mem, (unsigned long)size);
      std::free(mem);
    }
  }
};

struct allocator_base {
  void* operator new(std::size_t size)
   throw(std::bad_alloc) {
    return custom_allocator::allocate(size);
  }

  void* operator new [](std::size_t size)
   throw(std::bad_alloc) {
    return custom_allocator::allocate(size);
  }

  void operator delete(void* mem, std::size_t size)
   throw() {
    custom_allocator::deallocate(mem, size);
  }

  void operator delete [](void* mem, std::size_t size)
   throw() {
    custom_allocator::deallocate(mem, size);
  }
};

template<std::size_t T_size>
class buf : public allocator_base {
  char mem[T_size];
public:
  virtual ~buf() throw() {}
};

class buf2 : public buf<1234> {
  char mem2[1000];
};

int main() {
  buf<1024>* b1 = new buf<1024>;
  delete b1;

  buf2* b2 = new buf2;
  delete b2;

  b2 = new buf2[5];
  delete [] b2;

  return 0;
}
____________________________________________________________________

Humm... Is Comeau screwing up and compiling non-compliant code without so
much as a warning?

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