Re: This HAS to be UB...

From:
"Chris M. Thomasson" <no@spam.invalid>
Newsgroups:
comp.lang.c++
Date:
Sat, 4 Oct 2008 18:37:03 -0700
Message-ID:
<BMUFk.21515$%t.234@newsfe01.iad>
"Chris M. Thomasson" <no@spam.invalid> wrote in message news:...

"Victor Bazarov" <v.Abazarov@comAcast.net> wrote in message
news:gc39rg$q2m$1@news.datemas.de...

Chris M. Thomasson wrote:

Keep in mind that I am a C programmer; well, anyway here is the C++
program...

[...]

Well, the default implementation of the operator delete[] does *not* have
the "size" argument. In fact there are two allowed declarations of the
operator delete[]:

    void operator delete[](void* ptr) throw();

and

    void operator delete[](void* ptr, const std::nothrow&) throw();

I'm not sure what else to tell you.


I think that

void operator delete [](void*, std::size_t) throw();

is a valid declaration. I mean, even Comeau compiles the following program
without any warnings:
____________________________________________________________________
#include <cstdio>
#include <cstdlib>
#include <new>

struct custom_allocator {
 static void* allocate(std::size_t size)
  throw(std::bad_alloc) {
   void* const mem = std::malloc(size);
   if (! mem) {
     throw std::bad_alloc();
   }
   std::printf("custom_allocator::allocate(%p, %lu)\n",
     (void*)mem, (unsigned long)size);
   return mem;
 }

 static void deallocate(void* const mem, std::size_t size)
  throw() {
   if (mem) {
     std::printf("custom_allocator::deallocate(%p, %lu)\n",
       (void*)mem, (unsigned long)size);
     std::free(mem);
   }
 }
};

struct allocator_base {
 void* operator new(std::size_t size)
  throw(std::bad_alloc) {
   return custom_allocator::allocate(size);
 }

 void* operator new [](std::size_t size)
  throw(std::bad_alloc) {
   return custom_allocator::allocate(size);
 }

 void operator delete(void* mem, std::size_t size)
  throw() {
   custom_allocator::deallocate(mem, size);
 }

 void operator delete [](void* mem, std::size_t size)
  throw() {
   custom_allocator::deallocate(mem, size);
 }
};

template<std::size_t T_size>
class buf : public allocator_base {
 char mem[T_size];
public:
 virtual ~buf() throw() {}
};

class buf2 : public buf<1234> {
 char mem2[1000];
};

int main() {
 buf<1024>* b1 = new buf<1024>;
 delete b1;

 buf2* b2 = new buf2;
 delete b2;

 b2 = new buf2[5];
 delete [] b2;

 return 0;
}
____________________________________________________________________

Humm... Is Comeau screwing up and compiling non-compliant code without so
much as a warning?

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