is right.
"anon" <anon@no.invalid> schrieb im Newsbeitrag
news:gcf6hq$2b0$1@news01.versatel.de...
A.Gallus wrote:
I want to define a functor which calls methods of other classes via a
function pointer:
class play
{
public:
void operator ()
{
(*this.*fp)();
}
private:
void (OtherClass::*fp) ();
How is OtherClass defined?
};
Is this possible somehow?
Your example is missing main()
Anyway, you might want to read this:
http://www.parashift.com/c++-faq-lite/pointers-to-members.html
1. Do not top post. Read:
http://www.parashift.com/c++-faq-lite/how-to-post.html#faq-5.4
2. You should increase the warning level of your compiler and read
compiler errors carefully.
I copy&paste your example, but when I tried to compile your example (g++
4.1.3 without any additional options), I got this:
b2.cpp:21: error: invalid member function declaration
b2.cpp:29: error: ISO C++ forbids declaration of ?set_fp? with no type
b2.cpp:45: error: ?::main? must return ?int?
b2.cpp: In function ?int main()?:
b2.cpp:52: error: no match for call to ?(play) ()?
Here is the fixed version of your example:
class SomeClass
{
public:
void somefunc()
{
}
};
class play
{
public:
play( SomeClass * sc ){ this->scthis = sc; }
void operator () ()
{
(*scthis.*fp)();
}
void set_fp( void(SomeClass::*newfp)() )
{
this->fp = newfp;
}
private:
SomeClass * scthis;
void (SomeClass::*fp) ();
};
int main()
{
SomeClass * SC = new SomeClass();
play * p = new play(SC);
p->set_fp( &SomeClass::somefunc );
(*p)();
}