Re: vector<const T(*)> vs. vector<T(*)>
On Oct 30, 4:04 am, eiji.anonrem...@googlemail.com wrote:
Hi all,
I'm facing some uncertainty with const template arguments.
Maybe someone could explain the general strategy.
#include <vector>
int main(int arc, char** argv)
{
std::vector<const int> vec;
const int i = 5;
vec.push_back(i);
vec[0] = 4; //const has gone away
std::vector<const int*> pvec;
const int* pi = new int(5);
pvec.push_back(pi);
*(pvec[0]) = 4; // not possible because const, compile =
error
return 0;
}
From the first impression, it is not possible to create a vector of
const ints.
But you can do it with pointers.
This is exactly the reason I always use const on the right (correct)
side, especially when dealing with pointers/references.
'const int' is simply a special case way to write: 'int const'. or
with pointers 'const int *' is 'int const *'
Remember: declarations are read right to left from the variable name.
With this in mind the problem is extremely clear:
int const * - poiter to a constant int (pointer can change, integer
cannot)
int * const - constant pointer to an int (integer can change, pointer
cannot)
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