Re: Construct a string with char* taking ownership
On Oct 31, 2:30 am, "Nevin :-] Liber" <ne...@eviloverlord.com> wrote:
In article
<bb17c808-51f3-4eee-8ea0-d743448d7...@64g2000hsu.googlegroups.com>,
francis_r <francis.ramme...@gmail.com> wrote:
How can I construct a string using a char pointer without making a
copy, but simply by taking ownership of it?
You can't. How would std::string even know how to release the space you
give it?
If you need something to take ownership of a C string, you could always
do something like:
struct shared_c_string
{
shared_c_string(char* s = 0) : ptr(s, free) {}
operator const char*() const { return ptr.get(); }
private:
boost::shared_ptr<char> ptr;
};
you prohably should avoid free(0)
a nessted privare access functor like
struct deleter
{
void operator () (void *p)
{ if(p) free(p);
]
for the deleter is safer and since it is private can not be
modified by user like a void (&)(void *) can,
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