=?windows-1252?Q?Re=3A_error=3A_expected_primary=2Dexpression_before_=91int?= =?windows-1252?Q?'?=

From:
annamalai <annamalai.gurusami@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 2 Nov 2008 03:47:04 CST
Message-ID:
<ba836716-66f4-41d8-9121-45f2986fa242@e1g2000pra.googlegroups.com>
On Nov 1, 4:38 pm, annamalai <annamalai.gurus...@gmail.com> wrote:

On Nov 1, 10:58 am, raikanta.s...@gmail.com wrote:

template <typename T1>
void testAA()
{
   AA<T1> aa;
   int i = aa.get<int>();

}


Ultimately what you are trying to do here is to instantiate a template
member function without explicitly instantiating the template class.


I was wrong. As pointed out by Daniel Krugler, using the template
keyword will make the above C++ program well-formed. The appropriate
section to refer is the 14.2.4 ('Names of template specializations',
n2798.pdf, page 316). Here is the example provided in the draft:

struct X {
   template<std::size_t> X* alloc();
   template<std::size_t> static X* adjust();
};

template<class T> void f(T* p) {
   T* p1 = p->alloc<200>(); // ill-formed: < means less than
   T* p2 = p->template alloc<200>(); // OK: < starts template argument list
   T::adjust<100>(); // ill-formed: < means less than
   T::template adjust<100>(); // OK: < starts template argument list
}

I understand this better now.

Rgds,
anna

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