Re: Returning an array -- help needed

From:

Abhayks <abhaysahai@gmail.com>

Newsgroups:

comp.lang.c++

Date:

Fri, 12 Dec 2008 18:57:38 -0800 (PST)

Message-ID:

<209279ba-fbda-4bda-a6ec-dac6eb0cc04f@k1g2000prb.googlegroups.com>

On Dec 13, 10:13 am, Sam <s...@email-scan.com> wrote:

Abhayks writes:

Hi,
I am retuning to "C" after a long time and my basics are shatterred.
Not sure where I am making the mistake.
Please help.

#include<stdio.h>
#include<stdlib.h>

void foo( char ** ptr)
{
  int i;
   *ptr = malloc(255); // allocate some memory
   // strcpy( *ptr, "Hello World");
   for( i=0; i<5; i++)
     {
       *ptr[i]='a';

(*ptr)[i]='a';

}

(*ptr)[i]=0;

}

int main()
{
    char *ptr = 0;
    // call function with a pointer to pointer
    foo(&ptr );
    printf("%s\n", ptr);
    // free up the memory
    free(ptr);
    return 0;
}

Please advise why this is not working?

1) Operator precedence. [] carries higher precedence than the unary *
operator.

2) The string must be zero-terminated. malloc does not clear allocated
memory.

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God! how can I miss it.
I think 2 years of separation did the trick.
Thanks mate.
You really are a life saver.