Re: Copy a Base Class to a Derived Class

From:
Daniel Pitts <newsgroup.spamfilter@virtualinfinity.net>
Newsgroups:
comp.lang.c++
Date:
Mon, 12 Jan 2009 12:06:59 -0800
Message-ID:
<496ba2c9$0$12895$7836cce5@newsrazor.net>
iakko wrote:

Hello everybody,
first of all, sorry if the question I'm about to ask have been already
answered, but after some hours spent bothering google, I did not work
it out.

I have two classes:

class Base
{
public:
        Base() { k = 0; };
        ~Base() {};

        int k;
        void setK(int p) { k = p; };
        int getK() { return k; };

        void myMethod() { /* Code here */ };
};

class Derived : public Base
{
public:
        Derived() : Base() { i = 0; };
        ~Derived() {};

        int i;
        void setI(int p) { i = p; };
        int getI() { return i; };

        void myCoolMethod() { /* Code here */ };
};

Suppose I need to work with the derived class because I have to
implement many methods and I cannot touch the Base class since it's a
Qt class.

What I would like to do is find a way to "merge" an implementation of
a Derived class with another implementation of Base class, due to have
all the data for the Base class avaiable in the Derived class.

Casting is not sufficient since if I cast, I can use the Derived class
but I will lose all the personal data referred to it.

Let me explain with an tiny working example:

/* ### EXAMPLE STARTS ### */
#include <iostream>

class Base
{
public:
        Base() { k = 0; };
        ~Base() {};

        int k;
        void setK(int p) { k = p; };
        int getK() { return k; };

        void myMethod() { /* Code here */ };
};

class Derived : public Base
{
public:
        Derived() : Base() { i = 0; };
        ~Derived() {};

        int i;
        void setI(int p) { i = p; };
        int getI() { return i; };

        void myCoolMethod() { /* Code here */ };
};

int main() {
        Derived * d = new Derived();

        d->setI(10);
        printf("i: %d\n", d->getI());
        /* prints 10 */

        Base * b = new Base();

        b->setK(2);
        printf("k: %d\n", b->getK());
        /* prints 2 */

        d = reinterpret_cast<Derived *>(b);

        printf("i: %d -- k: %d\n", d->getI(), d->getK());
        /* prints 0 -- 2 !!! I want 10 -- 2 !!!*/

        return 0;
}
/* ### EXAMPLE STOPS ### */

Casting from Base to Derived loses all the Derived class information!!

I feel like there is a solution but I cannot imagine what is it.

Any suggestion is appreciated, thanks.

--
Iacopo


Try this instead:
  int main() {
          Derived * d = new Derived();

          d->setI(10);
          printf("i: %d\n", d->getI());
          /* prints 10 */

          Base * b = d;

          b->setK(2);
          printf("k: %d\n", b->getK());
          /* prints 2 */

          d = reinterpret_cast<Derived *>(b);

          printf("i: %d -- k: %d\n", d->getI(), d->getK());
          /* prints 2 -- 2 */

          return 0;
}

There is a difference between classes and instances! Make sure not to
confuse the two. When you have "new Derived()", you have actually
created a new Base along with a new Derived, so you don't need to have
another new Base();
--
Daniel Pitts' Tech Blog: <http://virtualinfinity.net/wordpress/>

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