Re: free() allocated memory twice..

.. is it an undefined behaviour??

You would expect this code to this
code ti give a segmentation fault but it doesnt.. Why??

Sample Code:
---------------
typedef struct {
 char name[10];
 int x;
} Employee;

int main()
{
 // allocate and fill e1
 Employee **e1 = (Employee**) malloc( 5 * sizeof(Employee*) );
 for(i=0 ; i<5 ; ++i) {
  e1[i] = (Employee*) malloc( sizeof(Employee) );
  fillEmployee(e1[i]);
 }

 // make shallow copy
 Employee **e2 = (Employee**) malloc( 5 * sizeof(Employee*) );
 for(i=0 ; i<5 ; ++i) {
  e2[i] = e1[i];
 }

 // free the copy
 for(i=0 ; i<5 ; ++i) {
  free(e2[i]);
 }
 free(e2);
 e2 = NULL;

 // free the original one
 for(i=0 ; i<5 ; ++i) {
  free(e1[i]);
 }
 free(e1);
 e1 = NULL;

 return 0;
}