Re: Smart pointer referencing its owner

From:
Pavel Minaev <int19h@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Mon, 9 Mar 2009 05:12:18 CST
Message-ID:
<89a124d7-381c-44bf-9f8b-328714f85394@13g2000yql.googlegroups.com>
On Mar 8, 3:45 am, Peter Dimov <pdi...@gmail.com> wrote:

On Mar 7, 7:03 am, Pavel Minaev <int...@gmail.com> wrote:
...

I see how that works for auto_ptr now, but I'm still not so sure about
shared_ptr. Again, consider the following (simplified, not thread-
safe, not deleter & weak_ptr aware, etc - I don't think all these are
relevant here) implementation of reset() for it:

    T* ptr;
    int* refcountptr;

    void reset(T* newptr = 0) {
       if (this->refcountptr && --*this->refcountptr == 0) {
          delete this->ptr;
          delete this->refcountptr;
       }

       if (this->ptr = newptr) {
         this->refcountptr = new int(1);
       } else {
         this->refcountptr = 0;
       }
    }


Broken.

What does the Standard say in this case?


template<class Y> void reset( Y* p );

   Effects: Equivalent to shared_ptr(p).swap(*this).


That question was about auto_ptr::reset(), not shared_ptr::reset() -
the latter is crystal clear now, thanks to your help, but I'm still
wondering about the former. C++03 still defines it thus:

   void reset(X* p=0) throw();
   Effects: If get() != p then delete get().
   Postconditions: *this holds the pointer p.

So no mention of swap(), and without it, I don't see it definitely
been required to go one or another way. If that is so, perhaps it
would make sense to align it with shared_ptr for C++0x?

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