Re: How to get the absolute address of an object's member function?

From:
Andrew Tomazos <andrew@tomazos.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 12 May 2009 11:17:32 -0700 (PDT)
Message-ID:
<557daae6-e3c2-4f9b-9c0f-9c5839749064@h23g2000vbc.googlegroups.com>
On May 12, 8:42 am, blackbiscuit <infozyzh...@gmail.com> wrote:

Dear all,

Suppose I have a class A which is defined as follows.

class A
{
    public:
        void f( int i )
        {
        }

};

A a;

How to get the absolute address of a.f( int )? Thank you very much!


Here is our member functor object with 1 parameter that will show you
the syntax for passing, storing and calling a member function:

class Task { public: virtual void execute() = 0; };

template<class C, class F, class P1>
class MethodTask1 : public Task
{
public:
    C* m_c; F m_f; P1 m_p1;

    MethodTask1(C* c, F f, P1 p1) : m_c(c), m_f(f), m_p1(p1) {}

    virtual void execute() { (m_c->*m_f)(m_p1); }
};

template<class C, class F, class P1>
Task* buildMethodTask(C* c, F f, P1 p1) { return new MethodTask1<C, F,
P1>, c, f, p1); }

// called like this:

A a = ...;

Task* task = buildMethodTask(&a, &A::f, 43);

task->execute();

delete(task);

(The real one uses smart pointers, but you get the idea)

Enjoy,
Andrew.

--
Andrew Tomazos <andrew@tomazos.com> <http://www.tomazos.com>

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