Re: Realizing memdup() compactly in C++

From:
Victor Bazarov <v.Abazarov@comAcast.net>
Newsgroups:
comp.lang.c++
Date:
Thu, 14 May 2009 11:21:02 -0400
Message-ID:
<guhcs3$e0c$1@news.datemas.de>
Nordl?w wrote:

On 14 Maj, 15:32, Victor Bazarov <v.Abaza...@comAcast.net> wrote:

Nordl?w wrote:

Han anybody written any snippet (template i guess) that realizes memdup
() using the operator new. Suggested name: new_duplicate.

What is it you're trying to accomplish with it? Are you trying to get
'memdup' to use the same *allocation function* as 'new'? Also, see FAQ
5.2, perhaps it's relevant.

V
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Ooops, memdup() was defined by me... Here's the definition:

static inline char *
memdup(const char *s, size_t n)
{
  char * t = (char*)malloc(n);
  memcpy(t, s, n);
  return t;
}


Uh... So, what's stopping you from replacing a call to malloc with a
'new[]' expression? Or do you want it to work with any type?

It's not a good idea to implement a memory "allocation" *function* using
'new[]', however, because, since it looks too much like 'malloc',
somebody will try to use 'free' on the pointer it returns, which has
undefined consequences, I believe. Currently I need to use 'free', and
it is consistent.

V
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