Re: Is there anything special I need to do in order to mix object files created by the C and the C++ compilers?

From:
pjb@informatimago.com (Pascal J. Bourguignon)
Newsgroups:
comp.lang.c++,comp.unix.programmer,comp.programming
Date:
Fri, 11 Sep 2009 03:40:42 +0200
Message-ID:
<87k506l0md.fsf@galatea.local>
Ramon F Herrera <ramon@conexus.net> writes:

The problem was fixed by the extern "C" statement, Josh.


Notice that you can wrap several declarations in a block:

extern "C"{
  #include <c_code.h>
  int foo(int);
}

How about the opposite, how should I refer to to an extern C++
function?

Let me guess:

extern "C++"


If that was that easy!

Since a lot of C code can be compiled by C++ compilers, the easiest is
to consider the C code as C++ code, and just call the other C++
functions without further ado.

However, if you have non-C++ conciscous C code, you might have to
review it and modify it slightly to avoid the things that are excluded
by C++. For example you cannot use the identifier 'new' in C++ code
since it's a keyword, so any C code that would it would have to be
edited. There are a number of similar gotchas.

Technically, the problem is that C++ function names are mangled, and
this mangling is implementation dependant! The signature of the
function is encoded into the external name of C++ functions.

So a C++ function such as int foo(int,char*); will actually be named
something like __Z3fooiPc in the object file.

From C code, compiled with a C program, you could call it as:

// C code:

extern int _Z3fooiPc(int i,char* c);

int f(){
    char a[]="abc";
    _Z3fooiPc(3,a);
}

Not funny.

The solution is to define C wrapper functions, in C++ (ie. you still
need the C++ compiler).

-------------------------------- c.cxx
// A C++ function:
int bar(int i,char* c){
    return(c[i]);
}

// A C++ function whose name won't be mangled:
extern "C" int foo(int i,char* c){
    return(bar(i,c));
}
---------------------------------

% g++ -c -o c.o c.cxx && nm c.o
00000000 T __Z3bariPc
00000000 A __Z3bariPc.eh
00000014 T _foo
00000000 A _foo.eh

Notably, in the case of C++ objects, your wrapper will have to
explicitely pass the 'this' parameter:

-------------------------------- o.cxx
// A C++ class:
class Example {
  int i;
public:
   Example(int aI):i(aI){}
   int foo(char* c){
      return(c[this->i]);
   }
};

// A C wrapper over the C++ class:
extern "C"{
   typedef void* ExampleP;
   ExampleP Example_new(int aI){ return new Example(aI); }
   Example_foo(ExampleP that,char* c){ return(((Example*)that)->foo(c)); }

}
---------------------------------

% g++ -c -o o.o o.cxx && nm o.o
0000006c s EH_frame1
0000002c T _Example_foo
00000000 A _Example_foo.eh
00000000 T _Example_new
000000d0 S _Example_new.eh
00000056 S __ZN7Example3fooEPc
000000ac S __ZN7Example3fooEPc.eh
00000046 S __ZN7ExampleC1Ei
00000088 S __ZN7ExampleC1Ei.eh
         U __Znwm
         U ___gxx_personality_v0

--
__Pascal Bourguignon__

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