Re: Multiple inheritance and pointer equivalence

From:
"io_x" <a@b.c.invalid>
Newsgroups:
comp.lang.c++
Date:
Fri, 27 Nov 2009 08:58:37 +0100
Message-ID:
<4b0f84ec$0$10444$4fafbaef@reader2.news.tin.it>
"Danny Woods" <dannywoodz@yahoo.co.uk> ha scritto nel messaggio
news:50skccrsex.fsf@gmail.com...

Hi all,

Given this simple program:

----

#include <cstdio>

class A { public: virtual ~A() {} };
class B { public: virtual ~B() {} };
class C : public A, public B { public: virtual ~C() {} };

int main(void)
{
 C *c = new C();
 A *a = c;
 B *b = c;

 printf("c: %p; a: %p; b: %p\n", c, a, b);

 delete c;
 return 0;
}

----

Is it to be expected that the addresses stored in a and b are different?
I've tried this with Visual C++ and Cygwin g++, with identical results.

The problem I have is that there are other subclasses of A and B that
are distinct, but that there's a special case where the combined
subclass, C, is required to fill both roles. When the code that cleans
up a and b runs later, I'll end up with double deletion unless I can


i not find in the example above no double free;
where is it?

Can i use "this" inside the distructor function?

------------------------------
#include <stdio.h>
#include <stdlib.h>
#define P printf
#define i8 signed char

class A{
 public:
 A(){ Aarr= (i8*) malloc(1024); }
 virtual ~A()
 {P("~A(); this=%p\n", this);
  free(Aarr);
  Aarr= (i8*) -1;
 }
 i8* Aarr;
};

class B{
 public:
 B(){ Barr= (i8*) malloc(1024); }
 virtual ~B()
 {P("~B(); this=%p\n", this);
  free(Barr);
  Barr= (i8*) -1;
  }
 i8* Barr;
};

class C : public A, public B{
  public:
  virtual ~C(){ P("~C(); this=%p\n", this); }
};

int main(void)
{ C *c = new C;
  A *a = c;
  B *b = c;

  if(c->Aarr==0||c->Barr==0)
        {P("No memory\n");
         goto end;
        }
  printf("c: %p; a: %p; b: %p\n", c, a, b);
end:;
  delete c;
  P("END\n");
  return 0;
}

------------------------------------
c: 00852FD4; a: 00852FD4; b: 00852FDC
~C(); this=00852FD4
~B(); this=00852FDC
~A(); this=00852FD4
END

reliably tell that a and b point to the same object, but the simple
'a == b' doesn't work here.

Cheers,
Danny.

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