How to create a shallow copy without calling a constructor?

From:
viboes <vicente.botet@wanadoo.fr>
Newsgroups:
comp.lang.c++.moderated
Date:
Sun, 3 Jan 2010 10:54:33 CST
Message-ID:
<3ea7ed4a-f75f-4bdc-b56f-0adeec98ad42@k19g2000yqc.googlegroups.com>
Hello,

I need to create a cache of a transactional object without using the
new operator nor the copy constructor of the class. This cache needs
only to copy the raw memory of the copied instance, is for that I have
called it shallow_clone

The following will create a deep copy and don't respect my
requirements

class C {
public:
  C* shallow_clone() {
      return new C(*this);
  }
};

I have looked at uninitialized_copy but if I have understood it
correctly, it calls the copy constructor.
I have tried with

class C {
public:
  C* shallow_clone() {
     C* p = reinterpret_cast<C>(new char[sizeof(C)]);
      if (p==0) {
          throw std::bad_alloc();
      }
      std::memcpy(p, this, sizeof(C));
      return p;
  }
};

But I suspect that this is not correct in general. Is this correct on
some particular cases? if yes on witch ones?
Is there a way to create such a cache instance without calling to the
constructor in a portable way using some low level C++ interface?

Thanks,
Vicente

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