Re: regarding Auto and decltype

Hello everybody.
In Scott Meyers lecture notes he states that one of the differences
between Auto and decltype is that the decltype does not evaluate the
expression.

I have a question regarding the evaluation of the expression, in the
next scenario what should I expect:

class B
{
public:
        B()
        {

        }
        virtual B* Clone()
        {
                cout << "B" << endl;
                return new B();
        }

};

class D : public B
{
public:
        D(){}
        virtual D* Clone()
        {
                cout << "D" << endl;
                return new D();
        }

};

int main()
{
        B* tmp = new D();
        auto test1 = tmp->Clone(); //returns D*!!!
        decltype(tmp->Clone()) test2 = tmp->Clone();
return 0;

}

Please note That D::Clone overloads with a different return type.

In my understanding if the "auto" is evaluating so it means that the
type of test1 should be D*, but VS10 understands different :) what am
I missing?