Re: Treating Foo<T>* as Foo<const T>*

From:
"naikrosh@gmail.com" <naikrosh@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Wed, 16 Jun 2010 08:03:56 CST
Message-ID:
<4ce51802-119a-4f5e-90b9-324f196c954d@t34g2000prd.googlegroups.com>

This is an idea and depends on what you are trying to accomplish.


Thanks all for your insights. Here is more background on what I am
interested in achieving. Perhaps it might help the discussion.

I need a custom smart pointer with special "binding" semantics as
described below :

  my_ptr<int> p1 = new int(2);
  my_ptr<int> p2 = p1; //Copy construction: now p1 & p2 are
permanently "bound" together.

  *p2 = new int(3); // now p1 also points to 3 (as p1 and p2 are
bound). 2 is freed.

  my_ptr<int> p3;
  p3 = p2; // Copy assignment: p3 takes a copy of *p2. This will not
bind p3 and p2

Binding can happen only through copy construction (not copy
asignment). Since multiple my_ptr can refer to the same object via
binding, reference counting is used to manage the lifetime of the
objects.

The basic skeleton of the internal representation is as follows:

 template<class T>
 struct my_ptr {
   ref_counted_ptr<T>* ptr;
 };

 template<class T>
 struct ref_counted_ptr {
   int ref_count;
   T* obj; //points to actual obj
 };

Essentially, my_ptr points to ref_counted_ptr which points to actual
obj and also stores the ref count.When two or more my_ptr are bound,
they point to the same ref_counted_ptr obj. Having a my_ptr point to a
diff object is acheived by updating the pointer inside ref_counted_ptr
which allows all bound my_ptr objects to now point to the new object.

My original questions comes from my inability to find a way to allow a
my_ptr<const T> to bind to my_ptr<T>.

Since T* can be used where a const T* is desired (same with
shared_ptr<T> & shared_ptr<const T> ). It is natural to expect similar
semantics out of my_ptr.

-Roshan

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