Re: derived class and virtual function

From:
"Francesco S. Carta" <entuland@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Fri, 13 Aug 2010 11:18:38 +0200
Message-ID:
<4c650dec$0$6843$5fc30a8@news.tiscali.it>
Stefan van Kessel <stefan.van.kessel@mytum.de>, on 13/08/2010 10:51:30,
wrote:

On 8/13/2010 10:29 AM, subramanian100in@yahoo.com, India wrote:

In Stanley Lippman's 'C++ Primer Fourth Edition', in page 564, the
following is mentioned:

"A virtual function in the derived class can return a reference or
pointer to a class that is PUBLICLY derived from the type returned by
the base class function."

I am unable to understand this sentence. Kindly explain it with
program sample.

Thanks
V.Subramanian


It allows you for example to write code like this (polymorphic copy)

#include <iostream>
class Foo
{
public:
virtual Foo* createCopy(){ return new Foo(*this); }
virtual void quack() { std::cout<<"I'm a foo"<<std::endl; }
virtual ~Foo(){}
};

class Bar : public Foo
{
public:
// notice that this createCopy returns a Bar* instead of Foo*
// which is a "pointer to a class that is PUBLICLY derived"
virtual Bar* createCopy(){ return new Bar(*this); }
virtual void quack() { std::cout<<"I'm a bar"<<std::endl; }
};

int main() {
Bar bar;
Foo& br = bar;
Foo* bp = br.createCopy();
bp->quack();
delete bp;
}


Ah, this makes more sense than my example, but I've been able to make it
work even declaring Bar::createCopy() as non-virtual, just for the records.

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