Re: Declaring a template class with two template params a friend in a non-template class

From:
=?ISO-8859-1?Q?Daniel_Kr=FCgler?= <daniel.kruegler@googlemail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Wed, 25 Aug 2010 17:04:57 CST
Message-ID:
<2956ae49-90f4-469d-ad25-0f41b90675ca@q1g2000yqg.googlegroups.com>
On 25 Aug., 19:22, A L <alapex0...@gmail.com> wrote:

I have an abstract class:

class Attribute { /* ...*/ };

Now I have another class:

template <typename T, typename U>
class Mgr
{
    static U *create(const std::string k, std::string v)
    {
        static T *p = 0;
        if (!p)
        {
            p = new T();
        }
        T &r = *p;
        U *a = const_cast<U*>(r.get(k));
        return a;
    }

};

Both of these classes are declared/defined in different header files.

The problem is that the constructors of Attribute class are private so
I have to declare the Mgr class a friend of Attribute. That's what I
have a problem doing - I am having a difficult time with the template
syntax when it comes to declaring a template class (with two template
parameters) a friend in a non-template class - I am getting lots of
compilation errors on the friend template declaration. Can any kind
sole tell me how I am supposed to do it? Declare a template class with
two template parameters a friend in a non-template class???


Yes, you just define Attribute as follows:

class Attribute {
  template<class, class>
  friend class Mgr;

  /* ...*/
};

This grants friend access to a template named Mgr with
two type template parameters.

HTH & Greetings from Bremen,

Daniel Kr?gler

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