Re: overloading operator delete[](void*, size_t) - possibly incorrect implementation of the language specification in Visual C++?

should s be equal in the call of new[] and in the call of delete[] in
the following example, as it is with g++?
With MSVC++2010 (and 2005) it is not.

#include <iostream>
using namespace std;
class C {
public:
        int j;

        void* operator new[]( size_t s ) {
                cout << "new[]: size_t=" << s << endl;
                return ::operator new[]( s );
        }
        void operator delete[]( void* ptr, size_t s ) {
                cout << "delete[]: size_t=" << s << endl;
        }};

int main() {
        C* x = new C[100];
        delete[] x;
        return 0;

}

Is this an incorrect implementation of the language specification in
Visual C++ or am I overlooking something?