Re: Using the ternary operator to initialize derived class objects

From:
"Bo Persson" <bop@gmb.dk>
Newsgroups:
comp.lang.c++
Date:
Mon, 31 Oct 2011 18:20:13 +0100
Message-ID:
<9h83mdFbjbU1@mid.individual.net>
Abhi wrote:

On Oct 31, 10:40 am, Goran <goran.pu...@gmail.com> wrote:

On Oct 31, 1:35 am, Dwight Army of Champions

<dwightarmyofchampi...@hotmail.com> wrote:

Hello! Suppose I have two derived classes Car and Bicycle that
derive from a base class Vehicle and an integer x. Why does the
following code give an "operand types are incompatible" error...

Vehicle* AnyVehicle = (x % 2 == 0) ? new Car() : new Bicycle();

...but the following code, which utilizes a simple if statement
to do exactly the same thing, compiles successfully?

Vehicle* AnyVehicle;

if (x % 2 == 0) {
AnyVehicle = new Car();}

else {
AnyVehicle = new Bicycle();

}

Is it even possible to initialize these objects with the ternary
operator?


The problem is, in "left : right" part of the ternary, you have two
unrelated types as far as the compiler is concerned. It tries to
deduct a type for that part, and does not try upcasting (note that
upcasting can get pretty messy if attempted on a more complicated
derivation case). You can use static_cast<Vehicle*> on any side to
work-around. The fact that you have Vehicle on the left does not
matter, as usual conversion rules are being applied on the "="
boundary, so the right side of "=" is done in on it's own.

Goran.


Could you please explain it in bit more detail. I m still confused
:(

Abhishek


The compiler has to figure out the resulting type of the ternary
expression. That works fine if the two subexpressions are of the same
type, or one is convertible to the other.

That they are both convertible to a third type doesn't help.

Bo Persson

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