Re: Clone an object with an abstract base class

From:
JiiPee <no@notvalid.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 12 Oct 2014 00:26:13 +0100
Message-ID:
<t0j_v.515012$Zu6.309162@fx06.am4>
On 11/10/2014 22:46, Urs Thuermann wrote:

I want to clone an object through a pointer to its abstract base
class. Say I have the following classes

     class B {
             virtual void foo() = 0; // abstract base class
     };
     class D1 : public B {
             virtual void foo();
     };
     class D2 : public B {
             virtual void foo();
     };

Then I can clone objects when I know the subclass of B

     void f1(D1 *d1, D2 *d2) {
             B *b1 = new D1(*d1);
             B *b2 = new D2(*d2);
     }

but not if I only have a pointer to the abstract base class

     void f2(B *b) {
             B *b1 = new B(*b); // error: cannot create a B
     }

With GCC and -std=c++11 I can write

     void f2(B *b) {
             B *b1 = new auto(*b);
     }

Is this the correct and preferred way in C++11?

In C++98 the only way I found is to add a pure virtual function

     B *B::clone() const

and

     B *D1::close() const { return new D1(*this); }
     B *D2::close() const { return new D2(*this); }

and then call b->clone() instead of the new operator.

Is there a way to do this in C++98 without the need to add a new
function like clone() in each derived class?

urs


How about checking the type of the *b object first and creating that
type of object:

void f2(B *b) {
     B *b1 = nullptr;
     if( typeid(*b).name() == typeid(D1).name() )
         b1 = new D1(*b1); // *b is type D1
     else if( typeid(*b).name() == typeid(D2).name() )
         b1 = new D2(*b1); // *b is type D2
}

and maybe also *b1 must be converted to its type like:
new D1( *((D1*)b1) )
?

Thats how I would do it propably :). At least a go-around. But there
might be better ways.

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