Re: initializing a vector with a sequence of 0, ..., N-1
Carl Barron <cbarron413@adelphia.net> schrieb:
In article <444A7408.20301@iitis.gliwice.pl>, Irek Szczesniak
<ijs@iitis.gliwice.pl> wrote:
I want to initialize a vector of N elements with the integer numbers
from 0 to N-1. What I came up with is this:
#include <vector>
#include <algorithm>
#include <iterator>
#include <iostream>
using namespace std;
int main()
{
vector<int> index(10);
for(int i = index.size(); i--; index[i] = i);
copy(index.begin(), index.end(),
ostream_iterator<int>(cout, "\n"));
return 0;
}
However, I don't like this, because I can introduce a but when coding
the "for" loop. Do you know some better way of doing it?
For instance, it would be cool to have something like this:
vector<int> index(seq<vector<int> >(0, 9));
Thanks for reading.
there is
template <class T>
class incr
{
T x;
public:
incr(const T &a):x(a){}
T operator () () {return x++;}
};
...
std::vector<int> foo;
std::generate_n(std::back_inserter(foo),10,incr<int> (0));
This looks really complicated in comparison to the for loop.
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