Re: new and delete

From:
"Howard" <alicebt@hotmail.com>
Newsgroups:
comp.lang.c++
Date:
Thu, 22 Jun 2006 18:09:55 GMT
Message-ID:
<T1Bmg.233471$Fs1.141212@bgtnsc05-news.ops.worldnet.att.net>
<junw2000@gmail.com> wrote in message
news:1150999034.048836.234840@r2g2000cwb.googlegroups.com...

Hi,
Below is a small code about memory allocation and deallocation.

#include <cstdlib>
#include <iostream>
using namespace std;

class X {
public:
 void* operator new(size_t sz) throw (const char*) {
   void* p = malloc(sz); //LINE1
   if (p == 0) throw "malloc() failed";
   return p;
 }

 void operator delete(void* p) {
   free(p);
 }

};

class Y {
 int filler[100];
public:

 // two arguments
 void operator delete(void* p, size_t sz) throw (const char*) {
   cout << "Freeing " << sz << " byte(s)" << endl; //LINE2
   free(p);
 };

};

int main() {
 X* ptr = new X; //LINE3

 // call X::operator delete(void*)
 delete ptr;

 Y* yptr = new Y;

 // call Y::operator delete(void*, size_t)
 // with size of Y as second argument
 delete yptr; //LINE4
}

My questions are:
When LINE3 is executed, LINE1 is executed. How is the variable sz
assigned sizeof(X)?

The output of the code is:
Freeing 400 byte(s)
When LINE4 is executed, LINE2 is executed. How does sz get the value
400?


It's magic! :-)

Actually, the C++ standard doesn't specify how or where new and delete keep
this information stored. That's up to the people who wrote the compiler to
decide. Most likely, some code is executed "behind the scenes" which
determines the size of the object to be created, and stores it in a "hidden"
location, for use later when deleting. (I suppose you could try checking
the generated machine code and see exactly what it's doing.)

-Howard

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