Re: Trap representations producing Undefined Behavior

From:
kingfox <foxapple@gmail.com>
Newsgroups:
comp.lang.c++
Date:
12 May 2007 07:36:27 -0700
Message-ID:
<1178980587.397612.254360@p77g2000hsh.googlegroups.com>
On 5=D4 12=C8=D5, =CF =CE=E74=CA=B142=B7=D6, thamizh.veri...@gmail.com =
wrote:

Hi,

I am new to this community. I have a doubt regarding trap
representations.

I read in IBM's website that something like this is legal:

int main(){
   int x=3;
   {
      int x=x;
   }

}

It said there that the scope of x in the inner block begins after the
initialization. So during the initialization process, the latter x in
"int x=x" refers to x in the outer scope. I understood that to an
extent.

But someone told me that something like this can produce Undefined
Behavior:

int main(){
   int x=3;
   {
       int x=x++;
   }

}

Why does this code snippet exhibit Undefined Behavior? I was told that
here x++ can prduce trap representation. I wasnt able to understand
that. According to me, the x++ refers to x in the outer scope. So why
can't this return the current value of x (in the outer scope) i.e. 3
and also increment it?


I don't know which compiler will make the latter x refer to outter
scope. I try three compiler (gcc, OpenWatcom, Borland C++ Builder),
they all treat the latter x as an uninitialized variable.

I was also told that something like this is well defined.

int main() {
struct X {X operator++(int) {return X();} } x;
x=x++;

}


x = x++ ==> x = X(); so, it's well defined.

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