Re: How do I use this typedef in a vector?
AalaarDB@gmail.com wrote:
Basically, how do I do this? If there is no legal way to do what I
want, why not? It seems very logical.
I want the array as a typedef for elegance and so I can do
treasury.front()[0] or treasury[0][0]
typedef int taxTable[8];//the type taxTable should be 8 ints
int size = sizeof(taxTable);//32, shows the array is working ok
taxTable taxes;
std::vector<taxTable> treasury;
treasury.push_back(taxes);
//error C2440: 'initializing' : cannot convert
//from 'const int [8]' to 'taxTable '
treasury.resize(1);
//error C2440: '<function-style-cast>' :
//cannot convert from 'int' to 'taxTable '
It's logical but unfortunately arrays are not logical in C/C++, never
have been. For instance you cannot have any array type as a parameter in
C/C++.
You can do close to what you want however
struct taxTable
{
int& operator[](size_t i) { return data[i]; }
int operator[](size_t i) const { return data[i]; }
int data[8];
};
std::vector<taxTable> treasury;
Add whatever other methods you need to taxTable and you'll get pretty close.
john
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