Re: Searching a vector with functionals
Matthias Buelow wrote:
I'm trying to implement a functor find_if, which takes a predicate,
and
searches a container (for example, vector) and returns (a reference
to)
the first element for which the predicate function returns true. I
can't
get it to work. Maybe someone can give me a hint? From my
understanding,
the call and the template-generated functions do match, typewise. The
problem appears to be that main()::f does not satisfy
std::unary_function<element_t&, bool>& but I don't understand why.
f() is a temporary, which cannot bind to a reference, but only a const
reference.
gcc (GCC) 4.1.2 20061115 (prerelease) (Debian 4.1.1-21) gives me the
following error message:
t.cc: In function 'int main()':
t.cc:35: error: no matching function for call to
'find_if(std::vector<foo, std::allocator<foo> >&, main()::f, foo&)'
t.cc:7: note: candidates are: element_t& find_if(container_t&,
std::unary_function<element_t&, bool>&, element_t&) [with
container_t =
std::vector<foo, std::allocator<foo> >, element_t = foo]
from the following code:
------------------------------snip------------------------------
using namespace std;
#include <functional>
#include <vector>
template<class container_t, typename element_t>
element_t &find_if(container_t &cont, unary_function<element_t &,
bool>
&fun, element_t ¬found)
{
[ snip ]
}
struct foo { int a; foo(int aa = 0): a(aa) {}; };
int main()
{
struct f: public unary_function<foo &, bool> {
bool operator()(foo &x) {
[ snip ]
}
};
vector<foo> fv;
foo notfound;
foo &x = find_if(fv, f(), notfound);
return 0;
}
------------------------------snap------------------------------
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