Re: Defining a cast on a templated class

From:
 Alexey Stepanyan <alexeystepanyan@yahoo.com>
Newsgroups:
comp.lang.c++
Date:
Tue, 13 Nov 2007 23:06:34 -0800
Message-ID:
<1195023994.524529.89060@50g2000hsm.googlegroups.com>
On 14 , 08:40, alan <almkg...@gmail.com> wrote:

I'm creating a sort-of "wrapper" class which (partly) acts like a
variable. Something like:
template<class t>
class cell{
  t curval;
public:
  /*public for debugging only - will be private in final version*/
  inline cell<t>& set_value(t v){ curval = v; return *this;}
  inline t get_value(){ return curval;}
  /*actual public interface*/
  /*assign to this value*/
  inline cell<t>& operator=(t v){ return set_value(v);}};

...
int
main(void){
  cell<int> v;
  v = 0;
  cout << "v = " << ((int)v);
  return 0;

}

However I can't figure out how to make the compiler do v.get_value()
when v is used in an int() context. Since this is templated, the only
conversion I want to support is something like cell<type> -> type.
Attempts to convert to unrelated types should signal an error.

I can't figure out the correct syntax to do this, unfortunately
(should probably look for better manuals, sigh).


1) all methods defined in class are implicitly inline so
   explicit "inline" is obsolete

2) it's better to pass parameters by const ref to operator= and
set_value
   because they don't modify the input value. Also get_value should be
const

3) use conversion operator to provide a conversion from cell<t> to t

   operator T() const
   {
      return curval;
   }

   to provide a conversion from t to cell<t> you can define a one
parameter constructor
   ( conversion constructor )

   cell( const t& curval_ ):curval( curval_ )
   {}

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