Re: operator overloading question

From:

"Daniel T." <daniel_t@earthlink.net>

Newsgroups:

comp.lang.c++

Date:

Thu, 10 Jan 2008 19:23:16 -0500

Message-ID:

<daniel_t-38BBB3.19231610012008@earthlink.vsrv-sjc.supernews.net>

none <mikem891@hotmail.com> wrote:

On Jan 10, 2:57?pm, "Daniel T." <danie...@earthlink.net> wrote:

Erik WikstrFm <Erik-wikst...@telia.com> wrote:

On 2008-01-10 13:47, none wrote:

I'm trying to overload the = operator using templates, but I have
some problems with one of the overloads, I would like to make
something like that:

intvariable = fooclass;

You can do that with a conversion operator:

#include <iostream>

class Foo
{
? int m_i;

public:
? Foo(int i) : m_i(i) {}
? operator int() { return m_i; }
};

int main()
{
? Foo f(4);
? int i = f;
? std::cout << i;
}

That's the unsafe choice. Better would be to make the constructor
explicit and provide a named conversion operator. That way you can tell
exactly what is going on at the call point and no mysterious temporaries
are created.- Hide quoted text -

- Show quoted text -

you have any code example, because I have no idea of how
I should do this. thanks

class Foo {
   int i;
public:
   explicit Foo( int i ): i( i ) { }
   int getI() const { return i; }
};

int main() {
   Foo f( 4 );
   int i = f.getI();
   std::cout << i;
}