Re: operator++ function

From:

"Daniel T." <daniel_t@earthlink.net>

Newsgroups:

comp.lang.c++

Date:

Sat, 23 Feb 2008 11:46:41 -0500

Message-ID:

<daniel_t-A78277.11464123022008@earthlink.vsrv-sjc.supernews.net>

Rahul <sam_cit@yahoo.co.in> wrote:

Hi Everyone,

I have the following code,

class A
{
public : ~A()
         {
             printf("in ~A\n");
         }
         A operator++(int)
         {
             A obj;
             printf("in operator function\n");
             return(obj);
         }
         A()
         {
             printf("in A\n");
         }
};

int main()
{
    A obj;
    printf("1\n");
    obj++;
    printf("2\n");
    return(0);
}

and the output i get is,

Double check your output. Or try this code:

int count = 0;

class A
{
   int id;
public :
   ~A() {
      cout << "Object: " << id << " destroyed.\n";
   }
   A operator++(int) {
      A obj;
      cout << "In post-inc of object: " << id << '\n';
      return obj;
   }
   A(): id( ++count ) {
      cout << "Creating object: " << id << '\n';
   }
   A(const A& o): id( ++count ) {
      cout << "Creating object: " << id << "as a copy of " << o.id <<
'\n';
   }
   A& operator=( const A& o ) {
      cout << "Assigning object: " << o.id << " to " << id << '\n';
   }
};

int main()
{
   A obj;
   cout << "at point 1\n";
   obj++;
   cout << "at point 2\n";
}

Your output should be:

Creating object: 1
at point 1
Creating object: 2
In post-inc of object: 1
Object: 2 destroyed.
at point 2
Object: 1 destroyed.