Re: question on vector<T> and T::operator=()
pelio wrote:
Ian Collins dixit:
subramanian100in@yahoo.com, India wrote:
Suppose 'Test' is a class:
class Test
{
public:
....
private:
Test& operator=(const Test& rhs)
{
cout << "Test::operator=() called" << endl;
}
};
Suppose I create
Test obj;
vector<Test> v;
v.push_back(obj);
Here I get compilation error because Test::operator=() is private (I
kept it as private ONLY for learning purpose). However if I keep
Test::operator=() as public, then it is not called for
'v.push_back(obj)'.
My doubt is, why does the compiler give error when Test::operator=()
is private though it is not needed for push_back() operation ?
The answer to your question is that the assignment operator may not be
called, but it is required to be public if defined.
$ cat tst1.cc ; echo ; make tst1 ; echo ; cat tst2.cc ; echo ; make tst2
; echo ; gcc --version
class A {
private:
A& operator=(const A& a) { return *this; }
};
int main() {}
g++ tst1.cc -o tst1
I though it pretty obvious from the context I was referring to a class
that is to be stored in a standard container.
--
Ian Collins.
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http://www.ynetnews.com/articles/0,7340,L-4003974,00.html
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