Re: glibc detected: double free or corruption
On Nov 15, 4:25 pm, "Victor Bazarov" <v.Abaza...@comAcast.net> wrote:
chuan wrote:
I define a class with a private dynamical member
Class A
{
double *data;
public:
A();
~A();
}
In constructor I assign a block memory to data,
A::A(){
data = new double [size];
}
and delete it in the desturctor
A::~A(){
delete [] data;
}
So far so good, but when I trying to overload some
arithmetic operator (+ or /), I receive the "glibc detected:
double free or corruption" error. Here is my code
A A::operator+(A add){
A tmp;
for (int i=0; i<size; i++)
tmp[i] = this->data[i] + add.data[i];
return tmp;
}
Please give me a hint.
Google "the rule of three c++" (without quotes, of course).
Actually, putting the quotes around "rule of three" might not be
a bad idea.
More generally, of course, I'd ask why he was using new[] and
delete[] to begin with. They're almost always a sign of bad
implementation; in this case, I fail to see why
std::vector<double> wouldn't do the job, much better.
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