Re: template function with automatically templatized return type.

From:
Vidar Hasfjord <vattilah-groups@yahoo.co.uk>
Newsgroups:
comp.lang.c++
Date:
Sat, 31 Jan 2009 14:09:04 -0800 (PST)
Message-ID:
<1e30f578-02a8-4a70-8c18-49049c96d580@i24g2000prf.googlegroups.com>
On Jan 30, 6:55 pm, Daniel Pitts
<newsgroup.spamfil...@virtualinfinity.net> wrote:

I have a Vector (as in math vector) template class.

template <typename component_t>
class Vector { /*...*/ };

It defines what you might expect for operators: =, [] +, -, * (as a
scalar multiply), /, etc...

I have some type which the result of (x*x) is not the same type as x.

OtherType operator*(const SomeType &, const SomeType &).

I would like to be able to define a generic operator* for Vector such
that the following works:

const Vector<OtherType> n = Vector<SomeType>() * SomeType();

I tried

template<typename component_in_t,
         typename component_out_t, typename scalar_t>
Vector<component_out_t> operator *(const Vector<component_in_t> &in,
                                    s=

calar_t scalar) {

    Vector<component_out_t> result;
    for (int i = 0; i < dimensions; ++i) {
      result[i] = in[i]*scalar;
    }
    return result;

}

But my compiler can't infer component_out_t.

Is there any way to do this?


Yes. While C++ doesn't directly support overloading on return type,
you can achieve the effect by returning a proxy that has conversion
operators for the required return types. The conversion operator then
performs the operation. For example:

const int dimensions = 2;

template <typename T>
struct Vector
{
  T v_ [dimensions];
  T& operator [] (int i) {return v_ [i];}
  const T& operator [] (int i) const {return v_ [i];}
};

template <typename T1, typename T2>
struct VectorMultiplication
{
  const Vector <T1>* v_;
  T2 s_;

  VectorMultiplication (const Vector <T1>& v, T2 s)
    : v_ (&v), s_ (s) {}

  template <typename T3>
  operator Vector <T3> () const {
    Vector <T3> r = {};
    for (int i = 0; i < dimensions; ++i)
      r [i] = (*v_) [i] * s_;
    return r;
  }
};

template <typename T1, typename T2>
VectorMultiplication <T1, T2>
operator * (const Vector <T1>& v, T2 s)
{
  return VectorMultiplication <T1, T2> (v, s);
}

// Test

#include <iostream>
#include <iterator>
#include <algorithm>

using namespace std;

template <typename T>
ostream& operator << (ostream& os, const Vector <T>& v)
{
  copy (&v [0], &v [0] + dimensions,
    ostream_iterator <T> (os, " "));
  return os;
}

void test_overloaded_return_type ()
{
  Vector <short> v = {1, 2};
  cout << v << endl; // 1 2

  Vector <int> r = v * 2;
  cout << r << endl; // 2 4
}

You can extend the proxy to a full expression template to optimize
your vector operations. Look up "expression template" for more
information.

Regards,
Vidar Hasfjord

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