Re: Design question: polymorphism after object creation

From:
Boris Rasin <rasin.boris@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 29 Mar 2009 10:06:36 -0700 (PDT)
Message-ID:
<4ca98426-b13f-4d84-986c-5211988055d6@q16g2000yqg.googlegroups.com>
On Mar 29, 2:34 am, Marcel M=FCller <news.5.ma...@spamgourmet.com>
wrote:

A union with a few types and a stable common base class would be nice.
If the base is virtual, the memory layout could match the requirements
in theory - but only in theory.
Like this:
+------------------------+
| Base |
+-------+--------+-------+
| File | Folder | Other |
+-------+ | |
+ free | +-------+
+-------+--------+-------+

This could turn into 4 different classes (if Base is not abstract)
without the need to change the Pointer to Base.


Just out of curiosity, here is what I came up with:

------------------ polymorph.h ------------------
#include <cstddef>
#include <type_traits> // or <boost\tr1\type_traits.hpp>
using std::tr1::aligned_storage;
using std::tr1::alignment_of;

template <typename T1, typename T2>
struct max_size
{
    static const std::size_t value = sizeof (T1) > sizeof (T2) ? sizeof
(T1) : sizeof (T2);
};

template <class base, class derived1, class derived2>
class polymorph
{
    //static_assert (std::has_virtual_destructor<base>::value);
    //static_assert (std::is_base_of<base, derived1>::value);
    //static_assert (std::is_base_of<base, derived2>::value);
public:
    polymorph() : object_ptr (reinterpret_cast<base*> (&object_space))
    {
        new ((void*)object_ptr) base;
    }

    ~polymorph()
    {
        object_ptr->~base();
    }

    base* operator -> () { return object_ptr; }

    template <class T>
    void change_type()
    {
        //base temp (std::move (*object_ptr));
        object_ptr->~base();

        object_ptr = const_cast<base* volatile> (object_ptr);

        new ((void*)object_ptr) T; // (std::move (temp));
    }
private:
    // Even though object_ptr always points to object_space,
    // it is needed to provide memory barrier when object type changes
    // (invalidate compiler's cache of object's const members including
vptr).

    base* object_ptr;

    typename aligned_storage<max_size<derived1, derived2>::value,
alignment_of<base>::value>::type object_space;
    //char object_space /*[[align(base)]]*/ [max_size<derived1,
derived2>::value];

};
------------------ polymorph.h ------------------

And the test code:

------------------ polymorph_test.cpp -----------
#include <iostream>
using std::cout;

#include "polymorph.h"

struct base
{
    base() { cout << "base()\n"; }
    virtual ~base() { cout << "~base()\n"; }
    virtual void func() { cout << "base::func()\n"; }
};

struct derived1 : base
{
    derived1() { cout << "derived1()\n"; }
    ~derived1() { cout << "~derived1()\n"; }
    virtual void func() { cout << "derived1::func()\n"; }
};

struct derived2 : base
{
    derived2() { cout << "derived2()\n"; }
    ~derived2() { cout << "~derived2()\n"; }
    virtual void func() { cout << "derived2::func()\n"; }
};

typedef polymorph<base, derived1, derived2> object_type;

void main()
{
    object_type obj;
    obj->func();

    obj.change_type<derived1>();
    obj->func();

    obj.change_type<derived2>();
    obj->func();
}
------------------ polymorph_test.cpp -----------
Here is the output:

base()
base::func()
~base()
base()
derived1()
derived1::func()
~derived1()
~base()
base()
derived2()
derived2::func()
~derived2()
~base()

When type is changed object is actually destroyed and re-created, so
you need some way to transfer state. But all references remain valid.
This implementation does provide some performance benefits compared to
standard proxy approach, but unless you really need those, I don't
know if I would use something like this in production code.

Boris.

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