Re: More keyword abomination by C++0x

From:
wasti.redl@gmx.net
Newsgroups:
comp.lang.c++.moderated
Date:
Wed, 29 Apr 2009 20:16:29 CST
Message-ID:
<e50fb6e2-64dd-4f5c-bb33-3e03e927fd3f@w35g2000prg.googlegroups.com>
On Apr 28, 8:53 pm, "Chris Morley" <chris.mor...@lineone.net> wrote:

"Nevin :-] Liber" <ne...@eviloverlord.com> wrote in messagenews:nevin-7C5A09.17343327042009@chi.news.speakeasy.net...

If you didn't have references, what would you return from operator=(),
operator++(), etc.?


Could have been done with pointers, but wasn't so doesn't really matter ;)

mytype* operator=(const mytype* Rhs) { ...; return this;}

Would have worked equally as well.


No, it wouldn't. If you defined this operator, then how would you
assign one pointer to another?
Or rather, how do you explain to a newcomer to the language that
mytype* operator=(const mytype* rhs);
is not used when doing this:

mytype *p = new mytype;

There is just so much duplication across pointers & references in my
opinion. References make for neater reading code:
int foo(int& a, int& b) {return a-b;} vs. int foo(int* a, int* b) {return
*a-*b;} & . instead of ->
But anytime you want 'object or NULL' behaviour I use pointers anyway.


Obviously. The fact that references can't be null is a great help in
most situations. For those where it isn't, you can of course use
pointers. But I prefer Boost.Optional.

Sebastian

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