Umm, function routing? For want of a better name...

Given, for instance

#include <iostream>

struct Operation{
   template<typename T>
   void operator%( T& t )
   {
      t += 10; // for eg.
      std::cout << "Operation::operator%()" << std::endl;
   }
};

struct A{
   int a;
   template<typename T>
   void func( T& t ){
      t % a;
   }
};

struct B{
   A a;
   int b;
   template<typename T>
   void func( T& t )
   {
      t % a; // would like this to call a.func()
      t % b;
   }
};

int main()
{
   Operation foo;
   B b;
   b.func( foo );

   return 0;
}

Can I get
   t % b;
in b.func() to call a.func()? I have played around with providing
overloaded %operator for A which calls func() but end up with
ambiguities I don't seem able to resolve. Also i'd prefer not to have
to provide an overload for each class I may wish to add. Are there
any techniques I can employ here to achieve my desired result?

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