Re: remove_if with a mask

From:
"Leigh Johnston" <leigh@i42.co.uk>
Newsgroups:
comp.lang.c++
Date:
Tue, 8 Jun 2010 15:41:28 +0100
Message-ID:
<vMmdnQdq1MsHy5PRnZ2dnUVZ7sWdnZ2d@giganews.com>
"eLVa" <elvadrias@gmail.com> wrote in message
news:f25e34ef-f8eb-4029-b86c-4005f2bfb6a4@s9g2000yqd.googlegroups.com...

On 8 juin, 10:09, "Leigh Johnston" <le...@i42.co.uk> wrote:

"Victor Bazarov" <v.baza...@comcast.invalid> wrote in message

news:hulh6q$46f$1@news.eternal-september.org...

On 6/8/2010 9:13 AM, eLVa wrote:

I have a simple problem : you are given a container, let's say a
vector of some objects, and a vector of bool which is to be treated as
a mask. You have to remove every element from the container for which
the mask is true.

basically, two iterators (one over the container and one over the
mask) iterates through their respective containers, removing elements
from the first when the second is true. I tried a few solutions, using
remove_if but I was not succesful !


Post what you have, post what didn't work, post your explanation on how
you expected it to work. Otherwise this looks too much like homework,
and
we don't do homework.


Ok ! Wait a minute there, it's not an homework, it's a question I'm
trying to resolve.
I thought that it was not wise to keep an iterator into a functor used
in remove_if. I wanted a direction, that's all.

So that's what I got :

template <class Z> struct maskChecker {
   public:
       maskChecker(const vector<bool> &mask) : it(mask.begin()) {}
       bool operator()(Z &) const { return *it ++; }
   private:
       mutable vector<bool>::const_iterator it;
};

template <class T> template<class Z>
void Selector<T>::compact(vector<Z> &data, const vector<bool> &mask) {
   if (data.size() != mask.size()) throw UnmatchedSize(data.size(),
mask.size());
   typename vector<Z>::iterator end = remove_if(data.begin(),
data.end(), maskChecker<Z>(mask));
   data.erase(end, data.end());
}

That's kinda working, what's your opinion ?

Does anybody have a solution that only uses stl, (i.e I don't want to
use boost) !


The solution involves a predicate that should keep the second iterator
(and increment it every time the operator() is called). The predicate
can probably be const, but has to keep non-const reference to the mask
iterator. Dereference the mask iterator to check and let the op() of
your
predicate essentially return that dereferenced bit.

V
--
I do not respond to top-posted replies, please don't ask


Fail. Your solution will not work on all implementations, it will fail
with
VC++ for example as VC++ first does a find_if to determine if it should
continue which results in more than N operator()'s being called.


I'm not sure I understand what you're saying, but I think it is what I
read somewhere about having an iterator inside a functor as not a very
good idea ... Is that it ?

/Leigh


It will not work as-is as an implementation is free to make copies of
predicates in its implementation of a particular algorithm.

/Leigh

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