Re: Template conversion operator ambiguity?

From:
=?ISO-8859-1?Q?=D6=F6_Tiib?= <ootiib@hot.ee>
Newsgroups:
comp.lang.c++
Date:
Wed, 21 Jul 2010 16:16:57 -0700 (PDT)
Message-ID:
<70fc5de4-402c-4fec-a533-d34e6389b029@u26g2000yqu.googlegroups.com>
On 22 juuli, 02:01, Ian Collins <ian-n...@hotmail.com> wrote:

While "porting" some existing code to g++, I ran into a problem with a
generic value class that uses a template conversion operator to return
values. Here's a stripped down version:

#include <string>

struct Value
{
   Value() {}

   template <typename T> operator T() { return T(); }

};

int main()
{
   Value v;

   int n(v);
   std::string s(v);

}

My original compiler is happy with the string initialisation, but g++
whinges about the conversion being ambiguous (edited to cut the noise):

example.cc:15: error: call of overloaded 'basic_string(Value&)' is ambigu=

ous

candidates are:
std::basic_string<_CharT, _Traits, _Alloc>::basic_string(const _CharT*,
const _Alloc&)

std::basic_string<_CharT, _Traits, _Alloc>::basic_string(const
std::basic_string<_CharT, _Traits, _Alloc>&)

std::basic_string<_CharT, _Traits, _Alloc>::basic_string(const _Alloc&)

But it will happily accept

std::string s = v;

So my question is, which compiler is correct?


I think g++ is correct, since it can not resolve what it is that you
pass to string constructor. Is it 2 parameters (with 1 default), 4
parameters (with 3 defaults) or 1 parameter (with also default value)?
Assignment has 1 parameter so there ... that is lot easier.

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