operator =

From:
Lasse <lars.dahlback@gmail.com>
Newsgroups:
comp.lang.c++.moderated
Date:
Thu, 23 Dec 2010 05:58:08 CST
Message-ID:
<0195de33-c44d-4274-be78-bf1a37855b50@s18g2000vby.googlegroups.com>
Hi!
I use VS2008 and get:

error C2679: binary '=' : no operator found which takes a right-hand
operand of type 'int' (or there is no acceptable conversion)

when compiling code below:

class MyBase {
   int a;
public:
   MyBase& operator = (int b) { a=b; return *this; }
   MyBase& operator << (int b) { a=b; return *this; }
};

class MyClass : public MyBase {
public:
// MyClass& operator = (int b) { *((MyBase*)this)=b; return *this; }
};

void func()
{
   MyBase X;
   X = 1;
   X << 1;

   MyClass Y;
   Y = 1; // Error
   Y << 1;
}

This is just a stripped example, but my real "problem" is the same.
Why does "operator <<" work in both cases but not "operator =" ?
If I uncomment the line in MyClass everything runs fine.
My idea was to have a base class with a bunch of nice functions and
operators in ONE place
without having to declare the same thing in the inherited class.

What am I missing?

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