Re: Implicit move constructor rules in c++0x still badly broken?
On Feb 23, 10:46 am, "Martin B." <0xCDCDC...@gmx.at> wrote:
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Code Example Tweak#2 from David's post @http://cpp-next.com/archive/2010/10/implicit-move-must-go/
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#define _GLIBCXX_DEBUG
#include <iostream>
#include <vector>
// An always-initialized wrapper for unsigned int
struct Number
{
Number(unsigned x = 0) : value(x) {}
operator unsigned() const { return value; }
private:
unsigned value;
};
struct Y
{
// Invariant: length == values.size(). Default ctor is fine.
// Maintains the invariant
void resize(unsigned n)
{
std::vector<int> s(n);
swap(s,values);
length = Number(n);
}
bool operator==(Y const& rhs) const
{
return this->values == rhs.values;
}
friend std::ostream& operator<<(std::ostream& s, Y const& a)
{
for (unsigned i = 0; i < a.length; ++i)
std::cout << a.values[i] << " ";
return s;
};
private:
std::vector<int> values;
Number length;
};
int main()
{
std::vector<Y> z(1, Y());
Y a;
a.resize(2);
z.push_back(a);
std::remove(z.begin(), z.end(), Y());
std::cout << z[1] << std::endl;};
- - -
Thank you for posting the code you wanted to discuss. I honestly had
no idea that this is what you wanted to discuss.
-Howard
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