Re: Returning a template depending on arguments

From:
daniele lugli <daniele.lugli@gmail.com>
Newsgroups:
comp.lang.c++
Date:
Sun, 28 Aug 2011 08:34:53 -0700 (PDT)
Message-ID:
<52826c8d-f8e5-4ded-8a1f-850df66a7848@c33g2000yqm.googlegroups.com>
On 28 Ago, 17:21, Alain Ketterlin <al...@dpt-info.u-strasbg.fr> wrote:

daniele lugli <daniele.lu...@gmail.com> writes:

template<int m, int n>
class SmallMatrix
{
    [...]
};
   SmallMatrix<m, n1> operator* (const SmallMatrix<n, n1> & f) cons=

t {

          [...]
   }


This can't work because, for a given (n,m), there must be one
instanciation of op* for each value of n1. You have to make it a
template member, i.e.,

template <int n1> SmallMatrix<m, n1> operator* ...

-- Alain.


Your suggestion works pretty fine:

template<int m, int n>
class SmallMatrix
{
    typedef double myData [m] [n];
    myData M;

public:
    SmallMatrix () {
        for (int i = 0; i < m; i++) {
            for (int j = 0; j < n; j++) {
                M[i][j] = 0.;
            }
        }
    }
    virtual ~SmallMatrix () {}
    operator myData & () {
        return M;
    }
        operator const myData & () const {
        return M;
    }
    SmallMatrix & operator= (const SmallMatrix & rhs) {
        for (int i = 0; i < m; i++) {
            for (int j = 0; j < n; j++) {
                M[i][j] = rhs[i][j];
            }
        }
                return *this;
    }
    template<int n1>
    SmallMatrix<m, n1> operator* (const SmallMatrix<n, n1> & f) const {
        SmallMatrix<m, n1> result;
        for (int i = 0; i < m; i++) {
            for (int j = 0; j < n1; j++) {
                result[i][j] = 0.;
                for (int k = 0; k < n; k++) {
                    result[i][j] += M[i][k] * f[k][j];
                }
            }
        }
        return result;
    }
};

Merci beaucoup!

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