Re: static vector (c style)

Yes if I add the headers all compile
well... But for me the code it
is too obscure... I'm not so expert
So I post how I would write it
in the way I understand some thing...
#include <stdio.h>

#include <string.h>

#include <iostream.h>

class myVect

{

public:

   static char s_vector[50];

   char us_vector[50];

   static bool trunc;

   myVect operator=(char s[])

   {int i;

     trunc = (((string)s).length() + 1 > sizeof s_vector) ? false : true;

     for (i = 0; i < sizeof s_vector; i++)

       s_vector[i] = us_vector[i] = s[i];

     return *this;

   }

};

char myVect::s_vector[50];

bool myVect::trunc;

int main(void)

{

   static myVect m1, m2;

   m1 = "Mickey Mouse";

   m2 = "Donald Duck";

   cout << "s: " << m1.s_vector << " us: " << m1.us_vector << endl;

   m1 = m2;

   cout << "s: " << m1.s_vector << " us: " << m1.us_vector << endl;

   system("pause");

   return 0;

}

__________________________________

#include <stdio.h>

#include <iostream.h>

char s_vectors[50*50]; // 0..2499

int index=0; /* index 0..49 50 string static

                 of max 50 chars */

class myVect

{public:

 char* s_vector;

 int trunc;

 char us_vector[50];

 

 myVect()

 {s_vector=(char*)s_vectors+(50*index);

  if(index>=2449) index = 0;

  else index+=50;

 }

 

~myVect(){}

 myVect& operator=(char* s)

 {int i;

  for(i=0; i<49 && s[i]!=0; i++)

     {s_vector[i]=s[i]; us_vector[i]=s[i];}

  s_vector[i]=0;

 us_vector[i]=0;

  trunc=(s[i]==0?0:1);

  return *this;

 }

 myVect& operator=(myVect& m)

 {int i;

  for(i=0; i<50; ++i)

     { s_vector[i]= m.s_vector[i];

      us_vector[i]=m.us_vector[i];

     }

  trunc=m.trunc;

  return *this;

 }

};

int main(void)

{myVect m1, m2;

 

 m1 = "Mickey Mouse";

 m2 = "Donald Duck";

 cout<<"s: "<<m1.s_vector<<" us: "<< m1.us_vector<<endl;

 m1 = m2;

 cout<<"s: "<< m1.s_vector<<" us: "<< m1.us_vector<< endl;

 return 0;

}